For the circuit shown, R 1 =R 2 =R 3 =R 9 =R 11 =107 Ohms, the rest of the resis

Question

For the circuit shown, R1=R2=R3=R9=R11=107 Ohms, the rest of the resistors are 214 Ohms.

a) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in series.

b) Without doing any simplification (or combination) identify they number of pairs of resistors (that is 2 resistors) that are in parallel.

c) Find R234 the equivalent resistance of resistors R2,R3, and R4.

I have tried quite a few times, but seem to be misunderstanding which are in parallel and which are in sequence.

For the circuit shown, R1=R2=R3=R9=R11=107 Ohms, the rest of the resistors are 214 Ohms. a) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in series. b) Without doing any simplification (or combination) identify they number of pairs of resistors (that is 2 resistors) that are in parallel. c) Find R234 the equivalent resistance of resistors R2,R3, and R4. I have tried quite a few times, but seem to be misunderstanding which are in parallel and which are in sequence.

Explanation / Answer

a) only 1, R2 and R3

b) 2 are

R8 and R 10

and R6 and R7

c) first combineR2 and R3

in series so

R23 = 107 + 107 = 214 ohms

now combines with R4

1/R = 1/214 + 1/214

R234 = 214/2 = 107 ohms

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