For the circuit shown, R 1 = R 3 = R 9 = R 11 = 106.0 Ohms, the rest of the resi

Question

For the circuit shown, R1= R3 = R9 = R11 = 106.0 Ohms, the rest of the resistors are 212.0 Ohms.

a) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in series.

b) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in parallel.

c) Find R12 the equivalent resistance of resistors R1, and R2.

d) Find R123 the equivalent resistance of resistors R1, R2, and R3.

e) Find R12345 the equivalent resistance of resistors R1, R2, R3, R4, and R5.

For the circuit shown, R1= R3 = R9 = R11 = 106.0 Ohms, the rest of the resistors are 212.0 Ohms. a) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in series. b) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in parallel. c) Find R12 the equivalent resistance of resistors R1, and R2. d) Find R123 the equivalent resistance of resistors R1, R2, and R3. e) Find R12345 the equivalent resistance of resistors R1, R2, R3, R4, and R5.

Explanation / Answer

series

r1 r2

r4 r5

r8 r10

r7 r10

b)parllel

r6 and r7 in parllel else arein series

c)R1and r2 in series

so R12=R1+R2

=106+212

=318 ohm

d)Req in parllel with r3

req=1/318+1/106

=0.003+0.009

=80.6ohm

e)R4 and r5 in series

so r4+R5

=212+212

=424

IN PARLlel with 80.6ohm

so 1/424+1/80.6

=0.002+0.012

=69.4ohm

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