Consider the circuit shown in the figure below. (Assume R 1 = 8.00 ?, R 2 = 1.20

Question

Consider the circuit shown in the figure below. (Assume R1 = 8.00 ?, R2 = 1.20 ?, and V = 6.00 V.)

(a) Calculate the equivalent resistance of the R1 and 5.00-? resistors connected in parallel.
?

(b) Using the result of part (a), calculate the combined resistance of the R1, 5.00-?, and 4.00-? resistors.
?

(c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00-? resistor.
?

(d) Combine the equivalent resistance found in part (c) with the R2 resistor.
?

(e) Calculate the total current in the circuit.
A

(f) What is the voltage drop across the R2 resistor?
V

(g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00-? resistor.
V

(h) Calculate the current in the 3.00-? resistor.
A

Explanation / Answer

R1 and 5 are in parallel = r1r2/r1+r2 = 8 x 5 /13 = 3.07 ohm

this is in series with 4ohm eq = 3.07 4 = 7.07 ohm

this in parallel with 3 ohm

eq = 7.07 x 3 / 7.07 + 3 = 2.11 ohm

this in series with R2

eq = 1.2 + 2.11 = 3.30 ohm

current = V/R = 6/3.3 = 1.818 A

vooltage drop = IR = 1.818 x 1.2 = 2.1818 V

Voltage across 3 ohm = 6 - 2.1818 = 3.818 V

current in 3 ohm

I = V/R = 3.818/3 = 1.27 A

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