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Consider the circuit shown in the figure below. (Assume R 1 = 7.00 ?, R 2 = 2.50

ID: 2300443 • Letter: C

Question

Consider the circuit shown in the figure below. (Assume R1 = 7.00 ?, R2 = 2.50 ?, and V = 9.00 V.)

(a) Calculate the equivalent resistance of the R1 and 5.00-? resistors connected in parallel.
?

(b) Using the result of part (a), calculate the combined resistance of the R1, 5.00-?, and 4.00-? resistors.
?

(c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00-? resistor.
?

(d) Combine the equivalent resistance found in part (c) with the R2 resistor.
?

(e) Calculate the total current in the circuit.
A

(f) What is the voltage drop across the R2 resistor?
V

(g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00-? resistor.
V

(h) Calculate the current in the 3.00-? resistor.
A

Explanation / Answer

a.)
Req.. = R1 || 5 = 7 * 5 / (5+7) = 35/12 = 2.916 ? >=========================< ANSWER

b.)
R3 = R1 || 5 + 4 = 2.916 + 4 = 6.916 ? >=========================< ANSWER

c.)
R4 = R3 || 3 = 6.916 * 3 / (6.916+3) = 2.092 ? >==================< ANSWER

d.)
R5 = R4 + R2 = 2.092+2.5 = 4.592 ? >=======================< ANSWER

e.)
Total current = v/R5 = 9 / 4.592 = 1.959 Amps >====================< ANSWER

f.)
VR2 = 2.5 * 1.959 = 4.897 volts >=============================< ANSWER

g.)
V(3ohms) = 9 - VR2 = 9-4.897 = 4.103 volts >====================< ANSWER

h.)
I(3ohms) = 4.103 / 3 = 1.367 Amps >=========================< ANSWER