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Block A in the figure below has mass 0.700kg , and block B has mass 2.90kg . The

ID: 1373380 • Letter: B

Question

Block A in the figure below has mass 0.700kg , and block B has mass 2.90kg . The blocks are forced together, compressing a spring S between them; then the system is released from rest on a level, frictionless surface. The spring, which has negligible mass, is not fastened to either block and drops to the surface after it has expanded. Block B acquires a speed of 1.15m/s

What is the final speed of block A?

How much potential energy was stored in the compressed spring?

Please explain

Block A in the figure below has mass 0.700kg , and block B has mass 2.90kg . The blocks are forced together, compressing a spring S between them; then the system is released from rest on a level, frictionless surface. The spring, which has negligible mass, is not fastened to either block and drops to the surface after it has expanded. Block B acquires a speed of 1.15m/s What is the final speed of block A? How much potential energy was stored in the compressed spring? Please explain

Explanation / Answer

a)

Initial vleocity of both blocks is zero.

From the law of conservation of momentum

           0 = m1v1 + m2v2

So the velocity of block A is

         v1 = - (m2v2)/m1

              = - (2.90 kg)(-1.15 m/s)/(0.70 kg)

               = 4.76 m/s

b)

From the law of conservation of energy , total energy of the system is conserved.

The potential energy stored in the spring = total kinetic energy of system

            U = (1/2)m1v1^2 + (1/2)m1v2^2

                = (1/2)(0.70 kg)(4.76 m/s)^2 + (1/2)(2.90 kg ) (1.15 m/s)^2

                = 9.85 J