Choose one: A. Vancomycin would inhibit transpeptidase activity by blocking acce
ID: 141314 • Letter: C
Question
Choose one:
A. Vancomycin would inhibit transpeptidase activity by blocking access to substrates.
B. Vancomycin would inhibit ß-lactamase activity by acting as an inhibitor.
C. Vancomycin would inhibit transpeptidase activity by acting as a suicide inhibitor.
D. Vancomycin would inhibit ß-lactamase activity by blocking access to substrates.
A.sequestering cytokines
B.facilitating cell migration
C.regulating the permeability of some membranes
D.serving as a nutrition source for gut bacteria
A. The -1,6 glycosidic bond in amylopectin does not require an enzyme for hydrolysis
.B. The residues connected by the -1,6 glycosidic bond are different in stachyose and amylopectin.
C. Amylopectin is absorbed by a different part of the intestine than stachyose.
D. Bacteria in the gut provide the glycosidase necessary to digest amylopectin, but there are no bacteria that express the correct enzyme for stachyose.
Explanation / Answer
1. Vancomycin is the drug of choice to treat gram positive bacterial infections where the bacteria are resistant to penicillins. Generally, vancomycin is the only drug of choice in case of methicillin resistant staphylococcus aureus. Vancomycin binds to the NAM and NAG (substrates) and prevent the action of transpeptidase enzyme and thus preventing the cell wall synthesis.
So, the correct answer is option A. Vancomycin would inhibit transpeptidase activity by blocking access to substrates.
Part2.
Based on the location, the proteoglycans are classified into intracellular, cell surface, pericellular and extracellular proteoglycans. Proteoglycans help us by preventing bacterial invasion by triggering immune response against them. Hence the option D is wrong. They do not serve as nutrition source of bacteria. All other options are correct.
The correct answers are options :
A.sequestering cytokines
B.facilitating cell migration
C.regulating the permeability of some membranes
Part 3.
Amylopectin is a polymer of glucose molecules. The glucose molecules are linked by (14) glycosidic bonds. For every 2430 glucose molecules, branching arises by (16) glycosidic bonds. Due to this type of branching, the amylopectin has many end point substrates which can be acted upon by the enzymes. Hence it is easily soluble.
Answer is option .B. The residues connected by the -1,6 glycosidic bond are different in stachyose and amylopectin