Mastering Physics: Homework #20 (phy 111) Google Chrome https:// mastering physi

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Mastering Physics: Homework #20 (phy 111) Google Chrome https:// mastering physics.com /myct/itemView? assignment ProblemID 51748475 &offset; next Session PHY 11 Fall 2015 Homework 20 (phy 111 Problem 13.26 Problem 13.26 Part A The piston of a hydraulic automobile lift is 0.310 m in What gauge pressure, in pascals, is required to lift a car with a mass of 1050 kg diameter gauge 168793.67 Pa. Submit My Answers Give U Incorrect, Try Again, 9 attempts remaining Part B Now express this pressure in atmospheres atm Submit My Answers Give Up signed in as Resources previous l 5 of 6 l next Provide Feedback Continue

Explanation / Answer

Solution:Pressure = Force ÷ Area

A)The gauge pressure is equal to the weight of the automobile divided by the area of piston.
Weight = 1050 * 9.8 = 10290 N
Area = * r^2, r = 0.155 m
Area = * 0.155^2

Pressure = 10290 ÷ ( * 0.155^2) = 136402.5 N/m^2 = 136402.5 Pa

2) 1 atmosphere = 1.013 * 10^5 Pa
Pressure = 136402.5 ÷ 1.013 * 10^5= 1.346 atm

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