Mastering Physics: Homework #20 (phy 111) Google Chrome https:// mastering physi
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Question
Mastering Physics: Homework #20 (phy 111) Google Chrome https:// mastering physics.com 51748476&offset; next Session PHY 11 Fall 2015 Help Close Signed Homework 20 (phy 111 Problem 13.6 Resources previous l 6 of 6 l return to assignment Problem 13.61 Part A A U-shaped tube open to the air at both ends contains some What is the gauge pressure at the water-mercury interface? mercury. A quantity of water is carefully poured into the left arm of the U-shaped tube until the vertical height of the water 2450 Pa column is 25.0 cm My Answers Give Up Correct Part B Calculate the vertical distance h from the top of the mercury in the right-hand arm of the tube to the top of the water in the left-hand arm h 231.5 Submit My Answers Give U Incorrect, Try Again, 7 attempts remaining Continue Provide FeedbackExplanation / Answer
Mercury is 13.6 = (13,600/1000) times greater than the density of water.
25 cm of water is equivalent to 25/13.6 = 1.838 cm of mercury.
Hence we can say that 1.838 8 cm of mercury was added to the left limb.
The new level being equal on both sides,
the left level depresses by 1.838/2 cm and
the right level rises by 1.838/2 = 0.919 cm or 9.19 mm