Mastering Physics: Chapter 19 Google Chrome Secure https: session masteringphysi

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Mastering Physics: Chapter 19 Google Chrome Secure https: session masteringphysics.com/myct/itemView?assignment Problem 75670218 PHYS212 SPRING20 17 Close Chapter 19 Problem 19.28 previous l 6 of 22 l next Problem 19.28 Part C Consider the circuit shown in (Figure 1). The batteries have emfs of E 9.0 V and E2 12.0 V and the resistors Determine the magnitudes of the currents in each resistor shown in the figure. Assume that each battery has internal resistance r 1.02 have values of R 28 S2 R2 -67 S2 and Ra 32 S2. Express your answers using two significant figures separated by commas. Figure Submit My Answers Give Part D Determine the directions of the cuments in each resistor Assume that each battery has internal resistance r 1.0 O Hright, 12 left, 13 down 11 left. I2 right, 13 up 11 left, 12 right, Is down 11 right, 12 left, B up Submit My Answers Give aback Continue 8:50 PM Ask me anything 2/21/2017

Explanation / Answer

1)

For the upper loop :

E1 = i1*R1 + (i1 + i2)*R2

So, 9 = i1*(28) + (i1 + i2)*67 --------- (1)

For the lower loop :

E2 = i2*R3 + (i1+i2)*R2

So, 12 = i2*32 + (i1+i2)*67 -------- (2)

Solving both the equations simultaneously ,

i1 = 0.018 A

i2 = 0.109 A

So, I1 = 0.018 A , I2 = (i1 + i2) = 0.127 A , I3 = i2 = 0.109 A <-------answer

directions = I1 (towards right)

I2 = (towards left)

I3 = towards up

2)

For the left loop:

16 = i1*10 + (i2 + i1)*14 -------- (1)

For the right loop :

11 = i2*15 + (i2 - i3)*22 ------- (2)

For the middle loop:

21 = (i3 - i2)*22 + (i3 + i1)*14 ----- (3)

Solving the 3 equations simultaneously:

i1 = 9.7*10^-5 A

i2 = 9.8*10^-4 A

i3 = 1.14*10^-3 A

So, current through battery E1 : I1 = i1 = 9.7*10^-5 A

Potential difference between a and b = Vab = i1*R1 - i2*R2

= 9.7*10^-5*10*10^3 - 9.8*10^-4*15*10^3

= -13.7 V <-------answer

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