Constants Part A You are watching an archery tournament when you start wondering

Question

Constants Part A You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. You find the arrow stuck in the ground 50.0 m away, making a 3.3° angle with the ground. Ignore all possible aer effects on the motion of the arrow. Use 9.80 m/s for the acceleration due to gravity. For how much time was the arrow in the air? Hint: use the horizontal and vertical problems to arrive at two equations in two unknowns (for example, the landing speed and the time of flight) SubmitP evious Answers Request Answer

Explanation / Answer

consider the motion along X-direction

vo = initial velocity = ?

X = horizontal distance travelled = 50 m

vf = final velocity = v Cos3.3

since there is no acceleration along X-direction

vf = vo

v Cos3.3 = vo

also

X = vo t

50 /(v Cos3.3) = t

v = 50/(t Cos3.3) eq-1

consider the motion along y-direction

Vf = final velocity = v Sin3.3

vo = initial velocity = 0 m/s

a = acceleration = 9.8

t = time of travel

using the equation

Vf = vo + at

v Sin3.3 = 0 + (9.8) t

using eq-1

(50/(t Cos3.3) ) Sin3.3 = 9.8 t

t = 0.54 sec

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