Initial pressure of gas in partition 1, P, = 800 kPa Initial temperature of gasi

Question

Initial pressure of gas in partition 1, P, = 800 kPa Initial temperature of gasi partition 1 , I, = 50°C Mass of ideal gas, m = 4 kg Considering the entire rigid tank as the system by applying the energy balance equation, E-Eur= AE, 0 = AU U, = U, T, = T. T. = 50°C The entropy change during the process is expressed as, s, -S =, Int +. Rin. As = m c, In +Rin ) = mR in = 4(0.287) (In 21 ) =0.795 kJK Consider the relation for entropy change and pressure, As = mR in (PIP) 0.795 = 4(0.287)ln (800/P. ) = 400.255 kPa As = 400 kPa

Explanation / Answer

hence solved

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