If you could do all 3 I would appreciate it but if not its ok just 5 would be su
ID: 2085910 • Letter: I
Question
If you could do all 3 I would appreciate it but if not its ok just 5 would be sufficient Thank you! :)
a = 3
b = 14
c = 3
d = 9
For Problems 5-7 assume X(t) is a zero-mean stationary Gaussian process with autocorrelation function RyG1-t2)-be-a-n a . . 5, (10%) What is the probability that the value of X(d) lies between c and d? 6. (15%) If X(c) is measured and found to have the value b, what is the probability that Give answers accurate to ±0.001 the value of X(d) lies between c and d? 7, (16%) What is the probability that X(c) and X(d) both lie between 0 and d?Explanation / Answer
Since answering 5 is sufficient i do that.
Probability in this case is defined using a autocorrelation function so X(d)=14*e^-I3-9I/3 i.e 1.89
Ans=1.89