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Please check answers and show your work. uman beings carrying the dominant T all

ID: 210833 • Letter: P

Question

Please check answers and show your work.

uman beings carrying the dominant T allele can taste the substance phenythiocarbamide (PTC). In a population in which the frequency of this allele is 0.04: a. What is the probability that a particulartaster ishomozwus b. What is the probability that a taster randomly mates with a non-taster? c. How many non-tasters would be expected in a population of 10,000 0 ) . LCO d0i individuals? 5 's) a. Thinking about the Hardy-Weinberg principles: a. (True/False) The Hardy-Weinberg principle directly relates allelic frequencies to phenotypic frequencies. mutation within a population. segregate multiple alleles, e.g. ABO blood type locus. b. (True/False) Hardy-Weinberg equilibrium assumes no migration and no -c. (True/False) The Hardy-Weinberg principle does not apply to genes that d. (True/False) Hardy-Weinberg equilibrium is neutral. Examine the following cells, from the same amphi stages of mitosis or meiosis bian species, shown in various \ //( ) a. Give the 2n number of chromosomes in this amphibian. IQ b. what cell division process and stage is represented in cell B7 c. i tofn Which of the cells above pictures a stage that follows chiasmata formation? m

Explanation / Answer

Means p=0.04

For homozygous we use p2 =0.0016

Hence, the probability of homozygous T (p2) =0.0016

Here, p=0.04/100=4%

Means, 4% are the taster for the PTC

Means 400 in 10,000

p-q=1

q=1-0.04

q=0.96

Means, 0.96/100=96%

So, 10,000-400=9600

The hardy Weinberg principle directly relates allelic frequency to the phenotypic frequency because from the allelic frequency we can calculate the phenotypic frequency.

The hardy Weinberg equilibrium assumes no migration and no mutation in a population because hardy Weinberg does not applied on these situations

The hardy Weinberg principle does not apply to genes that are segregate multiple allele like ABO blood group equilibrium because hardy Weinberg does not applied on multiple alleles.

The hardy Weinberg equilibrium is neutral because hardy Weinberg equilibrium is not neutral.