Consider the circuit shown in the figure below. (Assume R 1 =11.00 ? , R 2 =2.40
ID: 2148231 • Letter: C
Question
Consider the circuit shown in the figure below. (AssumeR1=11.00?,R2=2.40?, andV=9.00V.)
(a) Calculate the equivalent resistance of theR1and 5.00-?resistors connected in parallel.
(b) Using the result of part (a), calculate the combined resistance of theR1, 5.00-?, and 4.00-?resistors.
(c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00-?resistor.
(d) Combine the equivalent resistance found in part (c) with theR2resistor.
(e) Calculate the total current in the circuit.
(f) What is the voltage drop across theR2resistor?
(g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00-?resistor.
(h) Calculate the current in the 3.00-?resistor.
Explanation / Answer
a. equivalent rresistance=11x5/(11+5)=3.4375 ohms b.combined resistance=4+3.4375 = 7.4375 ohms c.equivalent resistance=7.4375x3/(7.4375+3)=2.1375 ohms d.combined resistance=2.1375+2.4=4.5375 ohms e.i=v/r=9/4.5375=1.9834 A f.v2=ixr2 = 1.9834x2.4=4.76 V g.voltage across the 3.00 ohm resistor=9-4.76=4.24 V h. current in the 3.00 ohm resistor=4.24/3=1.413 A