An object moves with constant acceleration 4.05 m/s2 and over a time interval re

Question

An object moves with constant acceleration 4.05 m/s2 and over a time interval reaches a final velocity of 12.2 m/s.
(a) If its initial velocity is 6.1 m/s, what is its displacement during the time interval?___m

(b) What is the distance it travels during this interval?

(c) If its initial velocity is ?6.1m/s, what is its displacement during the time interval?

(d) What is the total distance it travels during the interval in part (c)?

Explanation / Answer

a)12.2 = 6.1+(4.05*t) =>t = 1.50617284sec S = (6.1*1.50617284)+(0.5*4.05*(1.50617284^2)) = 13.78148149m b)S = (6.1*1.50617284)+(0.5*4.05*(1.50617284^2)) = 13.78148149m c)S = (-6.1*1.50617284)+(0.5*4.05*(1.50617284^2)) = 4.59382716m

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