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Safari File Edit View History Bookmarks Window Help 105 Fri 12:25:26 AM wrbassign.net Nowan'&methad; Practice winter 2 points RogsCalc2 5.1.001 My Notes Ask The figure below shows the velocity of an object over a 3-min interval mi/h 35 30 25 20 15 0.5 1.0 1.5 2.0 2.5 3.0 the interval (o, 3]. (Remember to convert from mi/hr to mi/min. Round your answer to two decimal places.) Determine the distance traveled over the interval [1, 2.5. (Remember to convert from mi/hr to mi/min. Round your answer to two decimal places) Subnmit Ansaer Save Progrees Pracice Arothter Versicn Pracice Arother Versian -13 points Rogacaic2 4,7.001. x) and initial guess xo to calculate X1, X2, and x3- (Round your answers to seven decimal places.) My Notos Ask You to 5 8 9Explanation / Answer
Up to .5 min the object was moving at 10mi/hr. So in .5 min it has moved 10/120 mi=.083 mi.
from .5 min to 1.5 min the object was moving at 20mi/hr. so in this 1 min interval, it has moved 20/60 mi=.33 mi.
from 1.5 min to 2.0 min the object was moving at 30mi/hr. so in this .5 min interval, it has moved 30/120 mi=.25 mi.
from 2 min to 3 min the object was moving at 25mi/hr. so in this 1 min interval, it has moved 25/60 mi=.42 mi.
So in [0,3] interval the object total moves (.083+.33+.25+.42)=1.083mi=1.08mi(rounded to two decimal places).
2nd part
from 1 min to 1.5 min the object was moving at 20mi/hr. so in this .5 min interval, it has moved 20/120 mi=.17 mi.
from 1.5 min to 2.0 min the object was moving at 30mi/hr. so in this .5 min interval, it has moved 30/120 mi=.25 mi.
from 2.0 min to 2.5 min the object was moving at 20mi/hr. so in this 1 min interval, it has moved 25/120 mi=.21 mi.
So in [1,2.5] interval the object total moves (.17+.25+.21)mi=.63 mi.