A sample of 9 days over the past six months showed that a dentist treated the fo

Question

A sample of 9 days over the past six months showed that a dentist treated the following numbers of patients: 23, 24, 20, 17, 16, 21, 23, 19, and 26. If the number of patients seen per day is normally distributed, would an analysis of these sample data reject the hypothesis that the variance in the number of patients seen per day is equal to 107. Use a 10 level of significance. a. State the null and alternative hypothesis. H_0: sigma^2 H_a: sigma^2 b. Calculate the value of the test statistic (to 2 decimals). c. The p-value is d. What is the your conclusion?

Explanation / Answer

Part-A

H0: 2=10

Ha: 210

Part-B

From following output test statistic F=8.80

Part-C

p-value=0.719

Part-D

Do not reject the null hypothesis and conclude that variance is not significantly different from 10

Test and CI for One Variance: Number of Patients

Method

Null hypothesis         -squared = 10

Alternative hypothesis -squared 10

The chi-square method is only for the normal distribution.

Tests

                                     Test

Variable            Method      Statistic DF P-Value

Number of Patients Chi-Square       8.80   8    0.719

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