A sample of 80 observations revealed that p = 0.89. At the 0.05 significance lev
ID: 3359058 • Letter: A
Question
A sample of 80 observations revealed that p = 0.89. At the 0.05 significance level, can the null hypothesis be rejected?
(Click to select)Do not reject/Reject H0.
[The following information applies to the questions displayed below.]
H1: 46
A sample of 42 observations is selected from a normal population. The sample mean is 29, and the population standard deviation is 4. Conduct the following test of hypothesis using the .05 significance level.
The following hypotheses are given. H0 : 0.83 H1 : > 0.83Explanation / Answer
a) Reject H0 if z > 1.64
b) std error =(p(1-p)/n)1/2 =0.042
test statsitic z=(phat-p)/std error =(0.89-0.83)/0.042=1.43
c)Do not reject
2)please reply which information to use : I m using below given information with mean =29 and std deviation =4
a) "One-tailed"-the alternate hypothesis is greater than direction.
b) decision rule : reject Ho if z>1.64
c) std error =std deviation/(n)1/2 =4/(42)1/2 =0.6172
test statistic z=(X-mean)/std error =(29-28)/0.6172=1.62
d)
Do not reject
There is insufficient evidence to conclude that the population mean is greater than 28
e)
p value =0.0526