Can someone explain in detail how to do this problem? Mineral oil can be used in
ID: 681607 • Letter: C
Question
Can someone explain in detail how to do this problem?Mineral oil can be used in place of mercury in manometers whensmall pressure changes are to be measured. What is the pressure ofan oxygen sample in mm of mineral oil if its pressure is 28.5 mmHg? (density of mineral oil = 0.88 g/mL ; density of Hg = 13.5g/mL) Can someone explain in detail how to do this problem?
Mineral oil can be used in place of mercury in manometers whensmall pressure changes are to be measured. What is the pressure ofan oxygen sample in mm of mineral oil if its pressure is 28.5 mmHg? (density of mineral oil = 0.88 g/mL ; density of Hg = 13.5g/mL)
Explanation / Answer
1 mmHg corresponds to the amount of force exerted upon a mL of mercury: 13.5g/mL * 9.8m/s^2 (In physics, F = ma). For mineral oil, therefore, 1mm mineral oil is .88g/mL * 9.8m/s^2. We thus see that 1mmHg corresponds to 15.341mm mineral oil. Thus, 28.5mmHg = 437.2mm mineral oil.