Identify the oxidizing agent and the reducing agent in each of the following. (T
ID: 740079 • Letter: I
Question
Identify the oxidizing agent and the reducing agent in each of the following. (Type your answer using the format Al for aluminum, [H]+ for H+ and [O]2- for O2-. Do not include state symbols in the answers.) (a) 8 H+(aq) + Cr2O72-(aq) + 3SO32-(aq) 2 Cr3+(aq) + 3 SO42-(aq) + 4 H2O(l) oxidizing agent Incorrect: Your answer is incorrect. reducing agent Incorrect: Your answer is incorrect. (b) 2 MnO4-(aq) + 10 Cl-(aq) + 16H +(aq) 5 Cl2(g) + 2 Mn2+(aq) + 8 H2O(l) oxidizing agent Incorrect: Your answer is incorrect. reducing agent Incorrect: Your answer is incorrect.Explanation / Answer
a) 8 H+(aq) + Cr2O72-(aq) + 3SO32-(aq)---------> 2 Cr3+(aq) + 3 SO42-(aq) + 4 H2O(l) the oxidizing agent is Cr2O72-, because its oxidation state is being changed from +6 to +3. I.e it itself is getting reduced and oxidizing the other substance. similarly the reducing agent is SO32-, because the oxidation state of sulfur is increased from +3 to +4. b) 2 MnO4-(aq) + 10 Cl-(aq) + 16H +(aq)-----------> 5 Cl2(g) + 2 Mn2+(aq) + 8 H2O(l) The oxidizing agent is MnO4-, because the oxidation state of Mn is reduced from +7 to +2 . similarly the reducing agent is Cl-, since its oxidation state is increased from -1 to 0