Identify the oxidizing agent and the reducing agent in the following. (Omit stat

Question

Identify the oxidizing agent and the reducing agent in the following. (Omit states-of-matter in your answer.) (a) Sn(s) + 2 H+(aq) Sn2+(aq) + H2(g) chemPad Help oxidizing agent Your answer contains an incorrect or incomplete chemical formula chemPad Help reducing agent Sorry, we were not able to generate useful feedback. (b) 2 H+(aq) + H2O2(aq) + 2 Fe2+(aq) 2 Fe3+(aq) + 2 H2O(1) chemPad Help oxidizing agent Your answer differs too much from the expected answer to provide useful feedback. chemPad Help reducing agent Your answer contains an incorrect or incomplete chemical formula

Explanation / Answer

1 a. Sn +2H+ ------>Sn2+ + H2

Oxidizing agent is H+ as it is gettiing reduced in the reaction.

Reducing agent is Sn as it is gettiing oxidised to Sn2+

b. 2H+ + H2O2 + 2 Fe2+ ------>Fe3+  + 2 H2O

Oxidizing agent is H2O2 as it is gettiing reduced in the reaction (O-1 to O2-)

Reducing agent is Fe2+ as it is gettiing oxidised to Fe3+

2. The question says Ag is the positive electrode. So Ag undergoes reduction

2 Ag+ (aq) + 2 e- -------> 2 Ag(s) Reduction

Pb undergoes oxidation

Pb (s) ---------> Pb2+ (aq) + 2e- Oxidation

Overall reaction: 2 Ag+ (aq) + Pb (s) ---------> 2 Ag(s) + Pb2+ (aq)

b. Cations flow towards cathode (Silver electrode)

Reduction takes place at the silver electrode.

Electrosn flow from lead electrode to silver electrode

3. [ Fe3+ + e- ------> Fe2+ ] * 3 ====>  3 Fe3+ + 3 e- ------> 3 Fe2+

Oxidation: Bi ------> Bi3+ + 3e-

Reduction: 3 Fe3+ + 3 e- ------> 3 Fe2+

----------------------------------------------------------------------------------------

   Bi (s) + 3 Fe3+ (aq) -------> Bi3+ (aq) + 3 Fe2+ (aq)

4 . Identify the oxidation half reaction:

Oxidation: Cd (s) -------> Cd2+ (aq) + 2 e-

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