Problem 19.80 Consider the reaction 3CH_4(g)-->C_3H_8(g) + 2H_2(g) Part B Calcul

Question

Problem 19.80 Consider the reaction
3CH_4(g)-->C_3H_8(g) + 2H_2(g)


Part B

Calculate Delta G at 298 K if the reaction mixture consists of 41atm of CH_4, 0.015atm of C_3H_8, and 2.1 * 10^-2amt of H_2.             
Express your answer using two significant figures.
Problem 19.80 Consider the reaction
3CH_4(g)-->C_3H_8(g) + 2H_2(g)


Part B

Calculate Delta G at 298 K if the reaction mixture consists of 41atm of CH_4, 0.015atm of C_3H_8, and 2.1 * 10^-2amt of H_2. Problem 19.80 Consider the reaction
3CH_4(g)-->C_3H_8(g) + 2H_2(g)


            
Express your answer using two significant figures.

Explanation / Answer

dG= dGo + RT ln K

first lets calclate dGo of reaction = 2 dGo H2 + dGo C3H8 -3 dGo CH4

= 0 -23 -3(-50.6) = 128.8 KJ/mol

kp = pH2^2 x pC3H8/pCH4 = 0.021^2 x 0.015 /( 41^3) = 9.6 x10^-11

dG = dGo + 2.3 RT log Kp

dG = 128800 + 2.3x8.314x298 log ( 9.6x10^-11)

= 128800 -61574.3

= 67226 J = 67 KJ/mol

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