Map pling The figure at the right illustrates the inverse relationship oxygen-Pr
ID: 810276 • Letter: M
Question
Map pling The figure at the right illustrates the inverse relationship oxygen-Proton Exchange in Hemoglobin between oxygen and proton binding to hemoglobin, as the Bohr Oxyhemoglobin more because of salt 11 bridges broken when oxygen binds Tissues 10.0 For purposes of calculation, hemoglobin can be modeled as a Hb simple monoprotic buffer dissociating one proton per subunit 9.0 as illustrated in the figure and in the following two equilibria: 8.0 pKa 7.8 Hbo. Blood pH 74 A HHb Hb pH 7.0 pka 6.7 Hbo, 6.0 HHbO H 5.0 Calculate the quantity (in mmol) of protons that will be released when 3.40 mmol of oxygen bind to deoxyhemoglobin at pH 7.4 4.0 and the pH then returns to 7.4, i e. in going from point A to point B on the curve. 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 Number Fraction Unprotonated mmol protons AO Previous Give Up & View solution Check Answer Next Ext HintExplanation / Answer
HA]/[A-]=10^(pK-pH)
[HHb]/[Hb]=10^(7.8-7.4)=2.51
fraction of HHb= 2.51/1+2.51=.715
nHHb= .715x 2.25= 2.43 mmol
[HHbO2]/[HbO2]=10^(6.7-7.4)=.200
fraction HHbO2= .200/1+.002=.374mm
2.43 -0.374= 2.057mmol