Consider the circuit shown in the figure below. (Let R = 7.60 Ohm and Delta V =

Question

Consider the circuit shown in the figure below. (Let R = 7.60 Ohm and Delta V = 17.0 V.) Find the equivalent resistance of the circuit in the figure above. Find the potential difference across each resistor. Find each current indicated in the figure above. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. A Find the power delivered to each resistor. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. W

Explanation / Answer

9 and R are in parallel

9*7.6/(9+7.6) =4.12 ohms

4.12 and 2.4 ohms are in series

4.12+2.4 =6.52 ohms

6.52 and R are in parallel

6,52*7.6/(6.52+7.6)=3.51 ohms

R,3.51 ohms and R are in series ,so equivalent resistance

Req=7.6+3.51+7.6 =18.71 ohms

b)

Current through each resistor

I1=V/Req=17/18.71 =0.9086 A

I2=0.9086*(6.52/6.52+7.6) =0.4196 A

I3=I-I2=0.9086-0.4196 =0.4890 A

I4=0.489*(9/9+7.6) =0.265 A

I5=I3-I4=0.224 A

Voltage across each resistor is

V=IR

Vac==0.9086*7.6 =6.91 Volts

Vce=2.4*0.489 =1.17 Volts

Vcd=7.6*0.4196 =3.19 Volts

Ved==7.6*0.265=2.01 Volts

Vfd=9*0.224=2.01 Volts

Vdb=0.9086*7.6=6.91 Volts

c)

Current across each resistor is

I1=0.9086 A

I2 =0.4196 A

I3 =0.4890 A

I4=0.265 A

I5=0.224 A

d)

Power delivered to each resistor

P=VI

Pac=6.91*0.9086=6.28 Watts

Pce=1.17*0.489=0.57 Watts

Pcd=3.19*0.4196 =1.34 Watts

Ped=2.01*0.265=0.53 Watts

Pfd=2.01*0.224=0.45 Watts

Pdb=6.91*0.9086=6.28 Watts

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