Consider the circuit shown in the figure below. (R = 15.0 ?.) http://www.webassi

Question

Consider the circuit shown in the figure below. (R = 15.0 ?.)

http://www.webassign.net/pse/p28-09alt.gif

(a) Find the current in the R = 15.0 ? resistor.

(b) Find the potential difference between points a and b.

Explanation / Answer

R and 5 O are in series => their equivalent resistance = 15 + 5 = 20 O This 20 O, 5 O and 10 O are in parallel. If R' is their equivalent resistance, 1/R' = 1/10 + 1/5 + 1/20 => R' = 320 / (32 + 64 + 10) = 2.85 O. R' is in series with 10 O => circuit resistance = 10 + 2.85 = 12.85 O => Main line current = 25/12.85 A = 1.94 A (b) P.D. across a and b = 25 - p.d. across 10 O = 25 - 1.94 * 10 = 5.6volt (a) Current in R = p.d. across R + 5 O branch / (R + 5) = 5.8 / (27+5) = 0.18125 A.

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