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Cours·Cotents » » MN 02 (Jan. 29) , Two metal plates O Timer Notes Evaluate Feedback-Print Two square metal plates are placed parallel to each other, separated by a distance d-1.52 cm. The plates have sides of length L-0.610 m. One or the plate these in6 toorin wilethe nther elate but charge Q. Calculate the magnitude of the electric field between the plates Submit Anawer Tries O/12 My general preferences on what is marked as NEW Hark NEW.pests.no.longer new Export NEW distance? Anonymous 1 Reply (Sun Jan 28 01:43:24 pm 2018 (EST) I got the correct answer without using the distance. Just wanted to make sure... So does the distance not matter when we're calculating the magnitude of the electric field between plates?7 Can someone please explain the reason behind that? Thanks NEW Re: distance? Michael David Vezmar Reply (Sun Jan 28 02:13:44 pm 2018 (EST)) Yeah distance doesn't matter for plates. It's on slide 12 of the w03. 12-ElectricFields-á slides. "The field is... constanti NEW Re: distance? Jaideep Singh Bepty (Sun Jan 28 03:21:07 pm 2018 (EST)) The electric field from an infinite uniformly charge plane is constant and uniform. To see why- apply Gauss's Law (or class lecture sides) If two of these planes are placed side by side parallel to each other, then the electric field on esther side of the planes and in between them is just the sum of the fields due to each individual y This is only true for infinite planes. However, two infinite planes are a very good approximation to two real finite pianes if 1. the separation of the planes is very small compared to the size of the planes (Le. d

Explanation / Answer

this is a parallel plate capacitor,

Capacitance, C = e0 A / d

and Q = C V

V = Q / C = Q d / e0 A

field strength = V / d = Q / (e0 A)

E = (1.62 x 10^-6) / (8.854 x 10^-12 x 0.610^2)

E = 4.92 x 10^5 N/C ........Ans

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