Class Management I Help Chapter 14 H.W. Begin Date: 11/13/2017 12:01:00 AM-Due D

Question

Class Management I Help Chapter 14 H.W. Begin Date: 11/13/2017 12:01:00 AM-Due Date: 12/8/2017 5:00:00 PM End Date: 12/8/2017 5:01:00 PM (20%) Problem 3: Suppose you want to operate an ideal refrigerator that has a cold temperature of-75°C, and you would like it to have a coefficient of performance of 8.5 What is the temperature, in degrees Celsius, of the hot reservoir for such a refrigerator? Grade Summa Deductions Potential cosO tan) acoso sino cotan) asin0 atano coshotan cotanhO Attempts remain ()% per attempt detailed view 0 ODegrees Radians Hint l give up! Hints: 0%, deduction per hint. Hints remaining: Feedback: 0% deduction per feedback.

Explanation / Answer

Let T1 be the temperature of hot reservoir and T2 be the temperature of cold reservoir. Then T2 = 273-7.5 = 265.5K

cof = 8.5 = T2/(T1-T2)

T1-T2 = T2/8.5 = 265.5/8.5 =31.2353

T1 = T2 + 31.2353 = 296.7353 K

T2 = 23.7353 0C

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