Problem 14.72 Acrylic acid (HC3H3O2) is used in the manufacture of paints and pl

Question

Problem 14.72

Acrylic acid (HC3H3O2) is used in the manufacture of paints and plastics. The pKa of acrylic acid is 4.25.

Part A

Calculate the pH in 0.130M acrylic acid.

Express your answer using three significant figures.

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Part B

Calculate the concentration of H3O+ in 0.130M acrylic acid.

Express your answer to two significant figures and include the appropriate units.

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Part C

Calculate the concentration C3H3O?2 in 0.130M acrylic acid.

Express your answer to two significant figures and include the appropriate units.

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Part D

Calculate the concentration of HC3H3O2 in 0.130M acrylic acid.

Express your answer to two significant figures and include the appropriate units.

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Part E

Calculate the concentration of OH? in 0.130M acrylic acid.

Express your answer to two significant figures and include the appropriate units.

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Part F

Calculate the percent dissociation in 0.0530M acrylic acid.

Express your answer to two significant figures and include the appropriate units.

Problem 14.72

Acrylic acid (HC3H3O2) is used in the manufacture of paints and plastics. The pKa of acrylic acid is 4.25.

Part A

Calculate the pH in 0.130M acrylic acid.

Express your answer using three significant figures.

SubmitMy AnswersGive Up

Part B

Calculate the concentration of H3O+ in 0.130M acrylic acid.

Express your answer to two significant figures and include the appropriate units.

SubmitMy AnswersGive Up

Part C

Calculate the concentration C3H3O?2 in 0.130M acrylic acid.

Express your answer to two significant figures and include the appropriate units.

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Part D

Calculate the concentration of HC3H3O2 in 0.130M acrylic acid.

Express your answer to two significant figures and include the appropriate units.

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Part E

Calculate the concentration of OH? in 0.130M acrylic acid.

Express your answer to two significant figures and include the appropriate units.

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Part F

Calculate the percent dissociation in 0.0530M acrylic acid.

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

HC3H3O2 -----> C3H3O2- + H+

0.13 - X..............X.............X

pKa = 4.25

=> Ka = 10^-4.25 = 5.623 x 10^-5

Ka = X^2 / 0.13 - X = 5.623 x 10^-5

=> X = 2.7 x 10^-3 M = [H+]

1) pH = - log [H+] = - log 2.7 x 10^-3 = 2.568

2) [H3O+] = 2.7 x 10^-3 M

3) [C3H3O2-] = X = 2.7 x10^-3 M

4) [HC3H3O2] = .13 - X = 0.2973 M = 0.30 M (Rounded to 2 decomal places)

5) [OH-] = 10^-14 / [H+] = 10^-14 / 2.7 x 10^-3 = 3.7 x 10^-12 M

6)

HC3H3O2 -----> C3H3O2- + H+

0.053 - X..............X.............X

pKa = 4.25

=> Ka = 10^-4.25 = 5.623 x 10^-5

Ka = X^2 / 0.053 - X = 5.623 x 10^-5

X = 1.73 x 10^-3 M

% dissociation = 1.73 x 10^-3 x 100 / 0.053 = 3.264 %

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