Consider the circuit sketched out The source has a voltage amplitude of 240V, R=

Question

Consider the circuit sketched out

The source has a voltage amplitude of 240V, R=120ohm and the reatanc of the capacitor is 650 ohm. The voltage amplitude across the capacitor is 620v

Part A

What is the current amplitude in the circuit?

I=?A

Part B What is the impedance

Z=?ohms

Part C

What two values can the reactance of the inductor have

Enter yoour answer as two numbers serparted with a comma?

XL=?ohms

Consider the circuit sketched out The source has a voltage amplitude of 240V, R=120ohm and the reactance of the capacitor is 650 ohm. The voltage amplitude across the capacitor is 620v What is the current amplitude in the circuit? What is the impedance Z=?ohms What two values can the reactance of the inductor have Enter your answer as two numbers separated with a comma?

Explanation / Answer

a)

Vc=IXc

I=Vc/Xc =620/650

I=0.9538 A

I=0.95 A (approx)

b)

Z=V/I =240/0.9538

Z=251.61 ohms

c)

Z=sqrt[R^2+(XL-Xc)^2]

251.61 =sqrt[120^2+[XL-650)^2]

251.61^2 =120^2+(XL-650)^2

(XL-650)^2 =48909.05

XL-650 =(+ or -) 221.15 ohms

so

XL -650 =221.15

XL1 =871.15 ohms

and

XL-650 =-221.15

XL2=428.85 ohms

so XL =428.85 ohms and 971.15 ohms

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