Consider the circuit shown in the figure below. (Assume R1 = 7.00 ?, R2 = 2.80 ?
ID: 1505342 • Letter: C
Question
Consider the circuit shown in the figure below. (Assume R1 = 7.00 ?, R2 = 2.80 ?, and V = 9.00 V.)
(a) Calculate the equivalent resistance of the R1 and 5.00-? resistors connected in parallel. ??
(b) Using the result of part (a), calculate the combined resistance of the R1, 5.00-?, and 4.00-? resistors. ??
(c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00-? resistor. ??
(d) Combine the equivalent resistance found in part (c) with the R2 resistor. ??
(e) Calculate the total current in the circuit. ? A
(f) What is the voltage drop across the R2 resistor? V
(g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00-? resistor. ?V
(h) Calculate the current in the 3.00-? resistor. ?A
4.00 5.00 3.00Explanation / Answer
a)
here
R1 and 5 are in parallel so 1/Req = 1/5 + 1/7
Req = 2.916 ohms
b)
These are in series so Req = 2.916 + 4 = 6.916 ohms
c)
These are in parallel so 1/Req = 1/3 + 1 / 6.916
Req = 2.092 ohm
d)
This Req is in series so Req = previous Req + 2.8
the equivalent resistance of the circuit is = 2.092 + 2.8 = 4.892 ohm
e)
I = V/ Req
I = 9 / 4.892 = 1.84 amp
f)
V2 = I * R2 = I * 2.8
V2 = 1.84 * 2.8 = 5.15 volts
g)
V3 = 9 -V2
V3 = 9 - 5.15 = 3.85 volts
h)
I3 = V3 / 3
I3 = 3.85 / 3 = 1.283 amp