Consider the circuit shown in the figure below. (Assume R1 = 11.0 , R2 = 1.95 ,

Question

Consider the circuit shown in the figure below. (Assume R1 = 11.0 , R2 = 1.95 , and V = 6.20 V 4.00 5.00 R2 3.00 (a) Calculate the equivalent resistance of the R1 and 5.00-2 resistors connected in parallel. (b) Using the result of part (a), calculate the combined resistance of the R1, 5.00-2 and 4.00-2 resistors. (c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00- resistor (d) Combine the equivalent resistance found in part (c) with the R2 resistor. (e) Calculate the total current in the circuit. (f) What is the voltage drop across the R2 resistor? (g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00- resistor. (h) Calculate the current in the 3.00-2 resistor.

Explanation / Answer

a)

R1 and 5 ohms are in parallel ,so equivalent resistance

=(1/11 +1/5)-1=3.4375 ohms

b)

3.4375 and 4 ohms are in series

=3.4375+4=7.4375 ohms

c)

7.4375 and 3 ohms are in parallel

=(1/7.4375 +1/3)-1=2.1377 ohms

d)

equivalent resistance

Req =2.1377+1.95=4.0877 ohms

e)

total current

I=V/Req =6.2/4.0877 =1.5167A

f)

Voltage across R2 is

V2=1.5167*1.95=2.9576 Volts

g)

Voltage across 3ohms is

V3=6.2-2.9576=3.2424 Volts

h)

Current in 3 ohms

I3=3.2424/3=1.0808A

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---